QUESTIONS

            QUESTIONS To SUCCESS

Their are some questions to solve so that your confidence could increase and can get your result where you stand, solve these all if you are doing practice for SSC, bank, bank P.O, AFCAT,ONGC,GATE and many more for any government job and private also. Today all companies and government takes the paper giving some aptitude questions in it or a new section like in SSC to clear that and taking a good score we have to attempt them for further increasing status and becoming eligible. As many of the people are eliminated in aptitude paper of jobs and in exams who are eliminated could be capable for that exam and job but due to this we are left behind.
>> So make some practice and solve these questions if you can solve these you can be able to solve many other good level questions. Many more questions will be provided to you in new post just for your sake attempt all and give your best to my question series to selected questions.
(Aptitude + Reasoning questions)

1)  A power unit is there by the bank of a river of 900 meters. A
cable is made from power unit to power a plant opposite to that of
the river of 2000mts. The cost of the cable below water is Rs. 5/-
per meter and cost of cable on the bank is Rs. 4/- per meter. Then
find out the amount to be invested to connect those two stations?
              Explanation:
Required length of wire = 2000 mts cost of cable below water = 900
* 5 = 4500 cost of cable on the bank of river= (2000 - 900) * 4 =
4400 Total cost = 4500 + 4400 = 8900.


2) A farmer had 20 hens. All but 2 died. How many hens are still
alive?
           Explanation:
"All but 2" means 2. So, all but 2 died means that there are only
two hens are alive and others were dead. So, the answer is 2.

3) At this series: 7, 10, 8, 11, 9, 12... What number should come
next?
         Explanation:
This is a simple alternating addition and subtraction series. In the
first pattern, 3 are added; in the second, 2 are subtracted.

4) A college has 10 basketball players. A 5-member team and a
captain will be selected out of these 10 players. How many
different selections can be made?
       Explanation:
We can select the 5 member team out of the 10 in 10C5 ways =
252 ways. The captain can be selected from amongst the
remaining 5 players in 5 ways. Therefore, total ways the selection
of 5 players and a captain can be made = 252*5 = 1260.

5) There are 3 gentlemen in a meeting: Mr. Yellow, Mr. Green and
Mr. Brown. They are wearing yellow, green and brown ties. Mr.
Yellow says: "Did you notice that the colors of our ties are different
from our names?" The person who is wearing the green tie says,
"Yes, you are right!" Do you know Brown is wearing what colour of
tie?
        Explanation:
We know that Mr. Yellow was not wearing a yellow tie because of
his statement. He also was not wearing the green tie because the
one wearing the green tie agreed to his statement. Therefore, Mr.
Yellow was wearing a brown tie. Mr. Green was wearing a yellow
tie. And Mr. Brown was wearing the green tie.

6)  A train can travel 50%faster than a car. Both start from point A
at the same time and reach point B 75 kms away from A at the
same time. On the way, however, the train lost about 12.5 minutes
while stopping at the stations. The speed of the car is:
Answer: 120KMPH

7) In a circular racetrack of length 100 m, three persons A, B and C
start together. A and B start in the same direction at speeds of 10
m/s and 8 m/s respectively. While C runs in the opposite at 15 m/
s. When will all the three meet for the first time after the start?
      Explanation:
Since the track is a circular track A and B will meet every 50
seconds. i.e. 100 / (10-8). Since it is a multiple of 50 they will be
meeting at the starting point every 50 Seconds. If you multiply 15 x
50 you will get 750 and after the second 50 it will be 1500. All of
them will meet at the starting point after 100s

8) A class of 100 students. 24 of them are girls and 32 are not.
Which base am I using?
Explanation:
Let the base be X. Therefore (X*X + X*0 + 0) = (2*X +4) + (3*X +
2), X * X = 5 * X + 6, X * X - 5 * X -6 = 0, (X- 6) (X+1) = 0 Therefore
base is 6.

9)  The cost of one pencil, two pens and four erasers is Rs.22
while the cost of five pencils, four pens and two erasers is Rs.32.
How much will three pencils, three pens and three erasers cost?
     Explanation:
x + 2y + 4z = 22 -------->1 5x + 4y + 2z = 32 ------->2 multiply eqn
(2) by 2 and substract from eqn(1) dividing by 3 we get 3x + 2y =
14--------->3 multiplying eqn (1) by 5 and subtracting eqn (2) then
divide by 6 we get y + 3z = 13---------->4 Adding eqn (3) and (4) we
get 3x + 3y +3z = 27

10) A is 20 percent more efficient than B. If the two persons can
complete a piece of work in 60 days. In how many days A working
alone can complete the work?
       Explanation:
Ratio of time taken by A and B is 1: 1.2 i.e. 5:6 Let the time taken
by A be 5x and by B be 6x , 1/5x + 1/ 6x = 1/60 => x =22. Time
taken by A = 5 * 22 = 110

11) On a certain island, 5%of the 10000 inhabitants are one-legged
and half of the others go barefooted. What is the least number of
Shoes needed in the island?
    Explanation:
In any case the one legged people will all require one shoe per
head. From the remaining, half will go barefooted and therefore
they need no shoes. And the rest will need two shoes per head.
And this works out at one shoe per person for the others.
Therefore for the whole population on the average one shoe per
head

12) Look at this series: 14, 28, 20, 40, 32, 64, what number should
come next?
       Explanation:
This is an alternating multiplication and subtracting series: First,
multiply by 2 and then subtract 8. 

13) Two pipes A and B can fill a tank in 24 min. and 32 min.
respectively. If both the pipes are opened simultaneously, after
how much time B should be closed so that the tank is full in 18
minutes?
Explanation:
Let B be closed after x minutes. Then, part filled by (A + B) in x
min. + part filled by an in (18 - x) min. = 1. X {1/24 + 1/32] + (18 -
x) X 1/24 = 1 or 7x/96 + (18 - x)/24 = 1 7x + 4(18 -x) = 96 or x=8
Hence, B must be closed after 8 minutes

14) At a car park there are 100 vehicles, 60 of which are cars, 30
are vans and the remaining are Lorries. If every vehicle is equally
likely to leave, find the probability of car leaving second if either a
lorry or van had left first :
      Explanation:
Let S be the sample space and A be the event of a van leaving
first. n(S) = 100 n (A) = 30 Probability of a van leaving first: P (A) =
30/100 = 3/10 Let B be the event of a lorry leaving first. n (B) =
100 - 60 - 30 = 10 Probability of a lorry leaving first: P (B) = 10/100
= 1/10 If either a lorry or van had left first, then there would be 99
vehicles remaining, 60 of which are cars. Let T be the sample
space and C be the event of a car leaving. n (T) = 99 n(C) = 60
Probability of a car leaving after a lorry or van has left: P(C) =
60/99 = 20/33



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